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4947128049383 = 13380548311491
BaseRepresentation
bin100011111111101011111…
…0011110101111011100111
3122111221101212012202011222
41013333113303311323213
51122023204240040013
614304402415050555
71020263305411412
oct107772763657347
918457355182158
104947128049383
1116380798a3503
1267a953210a5b
1329b6873249a0
14131629862b79
1588a45b7d508
hex47fd7cf5ee7

4947128049383 has 4 divisors (see below), whose sum is σ = 5327676360888. Its totient is φ = 4566579737880.

The previous prime is 4947128049379. The next prime is 4947128049407. The reversal of 4947128049383 is 3839408217494.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4947128049383 - 22 = 4947128049379 is a prime.

It is a super-3 number, since 3×49471280493833 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4947128049373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190274155733 + ... + 190274155758.

It is an arithmetic number, because the mean of its divisors is an integer number (1331919090222).

Almost surely, 24947128049383 is an apocalyptic number.

4947128049383 is a deficient number, since it is larger than the sum of its proper divisors (380548311505).

4947128049383 is a wasteful number, since it uses less digits than its factorization.

4947128049383 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380548311504.

The product of its (nonzero) digits is 41803776, while the sum is 62.

The spelling of 4947128049383 in words is "four trillion, nine hundred forty-seven billion, one hundred twenty-eight million, forty-nine thousand, three hundred eighty-three".

Divisors: 1 13 380548311491 4947128049383