4947333 has 4 divisors (see below), whose sum is σ = 6596448. Its totient is φ = 3298220.

The previous prime is 4947331. The next prime is 4947337. The reversal of 4947333 is 3337494.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4947333 - 2¹ = 4947331 is a prime.

It is a super-2 number, since 2×4947333² = 48952207625778, which contains 22 as substring.

It is a d-powerful number, because it can be written as 4⁷ + 9⁴ + 4⁸ + 7⁵ + 3³ + 3¹⁰ + 3¹⁴ .

It is a D-number.

It is a junction number, because it is equal to n+sod(n) for n = 4947294 and 4947303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4947331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 824553 + ... + 824558.

It is an arithmetic number, because the mean of its divisors is an integer number (1649112).

Almost surely, 2^4947333 is an apocalyptic number.

It is an amenable number.

4947333 is a deficient number, since it is larger than the sum of its proper divisors (1649115).

4947333 is a wasteful number, since it uses less digits than its factorization.

4947333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1649114.

The product of its digits is 27216, while the sum is 33.

The square root of 4947333 is about 2224.2601016967. The cubic root of 4947333 is about 170.3950788215.

The spelling of 4947333 in words is "four million, nine hundred forty-seven thousand, three hundred thirty-three".