Base | Representation |
---|---|
bin | 100100000011101001100… |
… | …0111111011111111011011 |
3 | 122112202101000202102001202 |
4 | 1020013103013323333123 |
5 | 1122143122134144340 |
6 | 14312331142104415 |
7 | 1021014235406402 |
oct | 110072307737733 |
9 | 18482330672052 |
10 | 4955639365595 |
11 | 1640747257336 |
12 | 68052971b10b |
13 | 29c412782879 |
14 | 131bd5dca639 |
15 | 88d92ec9c15 |
hex | 481d31fbfdb |
4955639365595 has 32 divisors (see below), whose sum is σ = 6475921056000. Its totient is φ = 3626165854080.
The previous prime is 4955639365591. The next prime is 4955639365597. The reversal of 4955639365595 is 5955639365594.
It is not a de Polignac number, because 4955639365595 - 22 = 4955639365591 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4955639365591) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 94225016 + ... + 94277594.
It is an arithmetic number, because the mean of its divisors is an integer number (202372533000).
Almost surely, 24955639365595 is an apocalyptic number.
4955639365595 is a deficient number, since it is larger than the sum of its proper divisors (1520281690405).
4955639365595 is a wasteful number, since it uses less digits than its factorization.
4955639365595 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86843.
The product of its digits is 2952450000, while the sum is 74.
Subtracting 4955639365595 from its reverse (5955639365594), we obtain a palindrome (999999999999).
The spelling of 4955639365595 in words is "four trillion, nine hundred fifty-five billion, six hundred thirty-nine million, three hundred sixty-five thousand, five hundred ninety-five".
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