Base | Representation |
---|---|
bin | 1001001111001111… |
… | …10100011010111101 |
3 | 110210122120201202012 |
4 | 10213213310122331 |
5 | 40124141421203 |
6 | 2140051541005 |
7 | 233622620324 |
oct | 44747643275 |
9 | 13718521665 |
10 | 4959717053 |
11 | 21156a3915 |
12 | b64bba765 |
13 | 6106c6325 |
14 | 3509b70bb |
15 | 1e064abd8 |
hex | 1279f46bd |
4959717053 has 4 divisors (see below), whose sum is σ = 4961274528. Its totient is φ = 4958159580.
The previous prime is 4959717047. The next prime is 4959717089. The reversal of 4959717053 is 3507179594.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4959717053 - 26 = 4959716989 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4959716992 and 4959717010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4959717043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 773951 + ... + 780332.
It is an arithmetic number, because the mean of its divisors is an integer number (1240318632).
Almost surely, 24959717053 is an apocalyptic number.
It is an amenable number.
4959717053 is a deficient number, since it is larger than the sum of its proper divisors (1557475).
4959717053 is a wasteful number, since it uses less digits than its factorization.
4959717053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1557474.
The product of its (nonzero) digits is 1190700, while the sum is 50.
The square root of 4959717053 is about 70425.2586292731. The cubic root of 4959717053 is about 1705.3713673509.
The spelling of 4959717053 in words is "four billion, nine hundred fifty-nine million, seven hundred seventeen thousand, fifty-three".
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