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49606391147 = 611231660617
BaseRepresentation
bin101110001100110001…
…010111010101101011
311202001011011202210012
4232030301113111223
51303043214004042
634442221042135
73404202240035
oct561461272553
9152034152705
1049606391147
111a046572985
1297450b634b
1348a7358491
142588350c55
151455044e82
hexb8cc5756b

49606391147 has 8 divisors (see below), whose sum is σ = 50460645312. Its totient is φ = 48753460800.

The previous prime is 49606391143. The next prime is 49606391173. The reversal of 49606391147 is 74119360694.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 49606391147 - 22 = 49606391143 is a prime.

It is a super-3 number, since 3×496063911473 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 49606391095 and 49606391104.

It is not an unprimeable number, because it can be changed into a prime (49606391141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 255218 + ... + 405399.

It is an arithmetic number, because the mean of its divisors is an integer number (6307580664).

Almost surely, 249606391147 is an apocalyptic number.

49606391147 is a deficient number, since it is larger than the sum of its proper divisors (854254165).

49606391147 is a wasteful number, since it uses less digits than its factorization.

49606391147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 661909.

The product of its (nonzero) digits is 979776, while the sum is 50.

The spelling of 49606391147 in words is "forty-nine billion, six hundred six million, three hundred ninety-one thousand, one hundred forty-seven".

Divisors: 1 61 1231 75091 660617 40297637 813219527 49606391147