4961335 has 4 divisors (see below), whose sum is σ = 5953608. Its totient is φ = 3969064.

The previous prime is 4961329. The next prime is 4961339. The reversal of 4961335 is 5331694.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4961335 - 2⁷ = 4961207 is a prime.

It is a super-2 number, since 2×4961335² = 49229689964450, which contains 22 as substring.

It is a Duffinian number.

4961335 is a lucky number.

It is a junction number, because it is equal to n+sod(n) for n = 4961297 and 4961306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4961339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496129 + ... + 496138.

It is an arithmetic number, because the mean of its divisors is an integer number (1488402).

Almost surely, 2^4961335 is an apocalyptic number.

4961335 is a deficient number, since it is larger than the sum of its proper divisors (992273).

4961335 is an equidigital number, since it uses as much as digits as its factorization.

4961335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 992272.

The product of its digits is 9720, while the sum is 31.

The square root of 4961335 is about 2227.4054413151. The cubic root of 4961335 is about 170.5556787909. Note that the first 3 decimals are identical.

The spelling of 4961335 in words is "four million, nine hundred sixty-one thousand, three hundred thirty-five".