Base | Representation |
---|---|
bin | 100100000110010101100… |
… | …1101010101001000011011 |
3 | 122120022021100020211000021 |
4 | 1020030223031111020123 |
5 | 1122241433002012340 |
6 | 14315124040451311 |
7 | 1021310263243210 |
oct | 110145315251033 |
9 | 18508240224007 |
10 | 4961412141595 |
11 | 16431398a0398 |
12 | 68167aa79b37 |
13 | 29cb22751a60 |
14 | 1321c296bb07 |
15 | 890cebcbe4a |
hex | 4832b35521b |
4961412141595 has 32 divisors (see below), whose sum is σ = 7758660809088. Its totient is φ = 2955680299008.
The previous prime is 4961412141577. The next prime is 4961412141611. The reversal of 4961412141595 is 5951412141694.
It is a cyclic number.
It is not a de Polignac number, because 4961412141595 - 219 = 4961411617307 is a prime.
It is a super-2 number, since 2×49614121415952 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 320704104 + ... + 320719573.
It is an arithmetic number, because the mean of its divisors is an integer number (242458150284).
Almost surely, 24961412141595 is an apocalyptic number.
4961412141595 is a deficient number, since it is larger than the sum of its proper divisors (2797248667493).
4961412141595 is a wasteful number, since it uses less digits than its factorization.
4961412141595 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 641423719.
The product of its digits is 1555200, while the sum is 52.
Subtracting 4961412141595 from its reverse (5951412141694), we obtain a palindrome (990000000099).
The spelling of 4961412141595 in words is "four trillion, nine hundred sixty-one billion, four hundred twelve million, one hundred forty-one thousand, five hundred ninety-five".
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