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4962073981477 = 15731605566761
BaseRepresentation
bin100100000110101001010…
…1010000011001000100101
3122120100222110121202122111
41020031102222003020211
51122244311414401402
614315313442201021
71021332550631434
oct110152252031045
918510873552574
104962073981477
1116434494464a8
12681824653171
1329cbc98bcba2
1413224681111b
158911cd629d7
hex48352a83225

4962073981477 has 4 divisors (see below), whose sum is σ = 4993679548396. Its totient is φ = 4930468414560.

The previous prime is 4962073981457. The next prime is 4962073981493. The reversal of 4962073981477 is 7741893702694.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3014636985441 + 1947436996036 = 1736271^2 + 1395506^2 .

It is a cyclic number.

It is not a de Polignac number, because 4962073981477 - 219 = 4962073457189 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4962073981427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15802783224 + ... + 15802783537.

It is an arithmetic number, because the mean of its divisors is an integer number (1248419887099).

Almost surely, 24962073981477 is an apocalyptic number.

It is an amenable number.

4962073981477 is a deficient number, since it is larger than the sum of its proper divisors (31605566919).

4962073981477 is a wasteful number, since it uses less digits than its factorization.

4962073981477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31605566918.

The product of its (nonzero) digits is 128024064, while the sum is 67.

The spelling of 4962073981477 in words is "four trillion, nine hundred sixty-two billion, seventy-three million, nine hundred eighty-one thousand, four hundred seventy-seven".

Divisors: 1 157 31605566761 4962073981477