496411000315 has 4 divisors (see below), whose sum is σ = 595693200384. Its totient is φ = 397128800248.

The previous prime is 496411000273. The next prime is 496411000369. The reversal of 496411000315 is 513000114694.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 496411000315 - 2¹¹ = 496410998267 is a prime.

It is a super-3 number, since 3×496411000315³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49641100027 + ... + 49641100036.

It is an arithmetic number, because the mean of its divisors is an integer number (148923300096).

Almost surely, 2^496411000315 is an apocalyptic number.

496411000315 is a deficient number, since it is larger than the sum of its proper divisors (99282200069).

496411000315 is an equidigital number, since it uses as much as digits as its factorization.

496411000315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99282200068.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 496411000315 in words is "four hundred ninety-six billion, four hundred eleven million, three hundred fifteen", and thus it is an aban number.