Base | Representation |
---|---|
bin | 101110001111011000… |
… | …101011101101100111 |
3 | 11202011012201011110012 |
4 | 232033120223231213 |
5 | 1303140431041042 |
6 | 34450425120435 |
7 | 3405244120112 |
oct | 561730535547 |
9 | 152135634405 |
10 | 49650252647 |
11 | 1a069300756 |
12 | 975792911b |
13 | 48b3474828 |
14 | 25900cb579 |
15 | 1458d0ae82 |
hex | b8f62bb67 |
49650252647 has 4 divisors (see below), whose sum is σ = 49737206376. Its totient is φ = 49563298920.
The previous prime is 49650252593. The next prime is 49650252787. The reversal of 49650252647 is 74625205694.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49650252647 - 214 = 49650236263 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 49650252595 and 49650252604.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (49650252347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43476008 + ... + 43477149.
It is an arithmetic number, because the mean of its divisors is an integer number (12434301594).
Almost surely, 249650252647 is an apocalyptic number.
49650252647 is a deficient number, since it is larger than the sum of its proper divisors (86953729).
49650252647 is an equidigital number, since it uses as much as digits as its factorization.
49650252647 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86953728.
The product of its (nonzero) digits is 3628800, while the sum is 50.
The spelling of 49650252647 in words is "forty-nine billion, six hundred fifty million, two hundred fifty-two thousand, six hundred forty-seven".
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