Base | Representation |
---|---|
bin | 1001010000100111… |
… | …11000011111011010 |
3 | 110211110022120202012 |
4 | 10220103320133122 |
5 | 40140121034213 |
6 | 2141143305522 |
7 | 234123036611 |
oct | 45023703732 |
9 | 13743276665 |
10 | 4971268058 |
11 | 21211732a9 |
12 | b68a4b2a2 |
13 | 612c0bb43 |
14 | 352342878 |
15 | 1e167d4a8 |
hex | 1284f87da |
4971268058 has 4 divisors (see below), whose sum is σ = 7456902090. Its totient is φ = 2485634028.
The previous prime is 4971268037. The next prime is 4971268063. The reversal of 4971268058 is 8508621794.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4933236169 + 38031889 = 70237^2 + 6167^2 .
It is a super-3 number, since 3×49712680583 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 4971267997 and 4971268015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1242817013 + ... + 1242817016.
Almost surely, 24971268058 is an apocalyptic number.
4971268058 is a deficient number, since it is larger than the sum of its proper divisors (2485634032).
4971268058 is a wasteful number, since it uses less digits than its factorization.
4971268058 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2485634031.
The product of its (nonzero) digits is 967680, while the sum is 50.
The square root of 4971268058 is about 70507.2198998088. The cubic root of 4971268058 is about 1706.6942573580.
The spelling of 4971268058 in words is "four billion, nine hundred seventy-one million, two hundred sixty-eight thousand, fifty-eight".
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