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497403427613 = 3465114354663
BaseRepresentation
bin1110011110011111000…
…11011111101100011101
31202112212220022011112212
413033033203133230131
531122140234140423
61020300505410205
750636056242431
oct7171743375435
91675786264485
10497403427613
11181a472a4204
1280497499965
1337b9c208001
141a1084349c1
15ce12bcd578
hex73cf8dfb1d

497403427613 has 4 divisors (see below), whose sum is σ = 497417816928. Its totient is φ = 497389038300.

The previous prime is 497403427607. The next prime is 497403427637. The reversal of 497403427613 is 316724304794.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 497403427613 - 28 = 497403427357 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (497403427693) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7142681 + ... + 7211982.

It is an arithmetic number, because the mean of its divisors is an integer number (124354454232).

Almost surely, 2497403427613 is an apocalyptic number.

It is an amenable number.

497403427613 is a deficient number, since it is larger than the sum of its proper divisors (14389315).

497403427613 is a wasteful number, since it uses less digits than its factorization.

497403427613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14389314.

The product of its (nonzero) digits is 3048192, while the sum is 50.

The spelling of 497403427613 in words is "four hundred ninety-seven billion, four hundred three million, four hundred twenty-seven thousand, six hundred thirteen".

Divisors: 1 34651 14354663 497403427613