Base | Representation |
---|---|
bin | 1110011110110111000… |
… | …01111011110100101101 |
3 | 1202120101220100211120111 |
4 | 13033123201323310231 |
5 | 31123043203021013 |
6 | 1020332444020021 |
7 | 50644046101000 |
oct | 7173341736455 |
9 | 1676356324514 |
10 | 497604345133 |
11 | 18203a753545 |
12 | 80532831611 |
13 | 37c01a23b0c |
14 | 1a126db5537 |
15 | ce2566973d |
hex | 73db87bd2d |
497604345133 has 8 divisors (see below), whose sum is σ = 580296612800. Its totient is φ = 426518009820.
The previous prime is 497604345131. The next prime is 497604345149. The reversal of 497604345133 is 331543406794.
It is not a de Polignac number, because 497604345133 - 21 = 497604345131 is a prime.
It is a super-2 number, since 2×4976043451332 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (49).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (497604345131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 725370423 + ... + 725371108.
It is an arithmetic number, because the mean of its divisors is an integer number (72537076600).
Almost surely, 2497604345133 is an apocalyptic number.
It is an amenable number.
497604345133 is a deficient number, since it is larger than the sum of its proper divisors (82692267667).
497604345133 is an equidigital number, since it uses as much as digits as its factorization.
497604345133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1450741552 (or 1450741538 counting only the distinct ones).
The product of its (nonzero) digits is 3265920, while the sum is 49.
The spelling of 497604345133 in words is "four hundred ninety-seven billion, six hundred four million, three hundred forty-five thousand, one hundred thirty-three".
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