Base | Representation |
---|---|
bin | 101110010110111101… |
… | …010000010000000011 |
3 | 11202111001201211020002 |
4 | 232112331100100003 |
5 | 1303420440430003 |
6 | 34511203510215 |
7 | 3411345620213 |
oct | 562675202003 |
9 | 152431654202 |
10 | 49777280003 |
11 | 1a123a82240 |
12 | 979238836b |
13 | 490388c249 |
14 | 25a2d16243 |
15 | 146504da88 |
hex | b96f50403 |
49777280003 has 4 divisors (see below), whose sum is σ = 54302487288. Its totient is φ = 45252072720.
The previous prime is 49777279997. The next prime is 49777280071. The reversal of 49777280003 is 30008277794.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 49777280003 - 212 = 49777275907 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 49777280003.
It is not an unprimeable number, because it can be changed into a prime (49777280803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2262603626 + ... + 2262603647.
It is an arithmetic number, because the mean of its divisors is an integer number (13575621822).
Almost surely, 249777280003 is an apocalyptic number.
49777280003 is a deficient number, since it is larger than the sum of its proper divisors (4525207285).
49777280003 is a wasteful number, since it uses less digits than its factorization.
49777280003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4525207284.
The product of its (nonzero) digits is 592704, while the sum is 47.
It can be divided in two parts, 497772 and 80003, that added together give a palindrome (577775).
The spelling of 49777280003 in words is "forty-nine billion, seven hundred seventy-seven million, two hundred eighty thousand, three".
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