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4985613201803 = 133493294133359
BaseRepresentation
bin100100010001100110110…
…1101000011000110001011
3122122121201221211001110112
41020203031231003012023
51123141013434424203
614334205321304535
71023125066665103
oct110431555030613
918577657731415
104985613201803
1116524287500a3
126862b393514b
132a21ab5b6b20
1413343ab84203
1589a496866d8
hex488cdb4318b

4985613201803 has 16 divisors (see below), whose sum is σ = 5384831088000. Its totient is φ = 4588641083520.

The previous prime is 4985613201799. The next prime is 4985613201823. The reversal of 4985613201803 is 3081023165894.

It is a happy number.

It is not a de Polignac number, because 4985613201803 - 22 = 4985613201799 is a prime.

It is a super-2 number, since 2×49856132018032 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4985613201823) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 149436638 + ... + 149469996.

It is an arithmetic number, because the mean of its divisors is an integer number (336551943000).

Almost surely, 24985613201803 is an apocalyptic number.

4985613201803 is a deficient number, since it is larger than the sum of its proper divisors (399217886197).

4985613201803 is a wasteful number, since it uses less digits than its factorization.

4985613201803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66662.

The product of its (nonzero) digits is 1244160, while the sum is 50.

The spelling of 4985613201803 in words is "four trillion, nine hundred eighty-five billion, six hundred thirteen million, two hundred one thousand, eight hundred three".

Divisors: 1 13 349 4537 32941 33359 428233 433667 11496409 11642291 149453317 151349783 1098878819 14285424647 383508707831 4985613201803