Base | Representation |
---|---|
bin | 101110100100001100… |
… | …000010101110001011 |
3 | 11210001112102121022000 |
4 | 232210030002232023 |
5 | 1304344302314210 |
6 | 34545213402043 |
7 | 3420012462636 |
oct | 564414025613 |
9 | 153045377260 |
10 | 49999260555 |
11 | 1a228308542 |
12 | 9834799323 |
13 | 493a87129a |
14 | 25c45bac1d |
15 | 147979aac0 |
hex | ba4302b8b |
49999260555 has 64 divisors (see below), whose sum is σ = 89696747520. Its totient is φ = 26424050688.
The previous prime is 49999260523. The next prime is 49999260599. The reversal of 49999260555 is 55506299994.
49999260555 is a `hidden beast` number, since 499 + 9 + 92 + 6 + 0 + 5 + 55 = 666.
It is not a de Polignac number, because 49999260555 - 25 = 49999260523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49999260492 and 49999260501.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 21995899 + ... + 21998171.
It is an arithmetic number, because the mean of its divisors is an integer number (1401511680).
Almost surely, 249999260555 is an apocalyptic number.
49999260555 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
49999260555 is a deficient number, since it is larger than the sum of its proper divisors (39697486965).
49999260555 is a wasteful number, since it uses less digits than its factorization.
49999260555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3697 (or 3691 counting only the distinct ones).
The product of its (nonzero) digits is 39366000, while the sum is 63.
The spelling of 49999260555 in words is "forty-nine billion, nine hundred ninety-nine million, two hundred sixty thousand, five hundred fifty-five".
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