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49999994055005 = 59999998811001
BaseRepresentation
bin10110101111001100001111…
…11000100110100101011101
320120000221201112222020010212
423113212013320212211131
523023144441434230010
6254201402525542205
713350244315040561
oct1327460770464535
9216027645866125
1049999994055005
1114a27973168575
125736400a14965
1321b8c96421027
14c4c0268db6a1
155ba934388505
hex2d7987e2695d

49999994055005 has 4 divisors (see below), whose sum is σ = 59999992866012. Its totient is φ = 39999995244000.

The previous prime is 49999994054999. The next prime is 49999994055041. The reversal of 49999994055005 is 50055049999994.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27419497467769 + 22580496587236 = 5236363^2 + 4751894^2 .

It is a de Polignac number, because none of the positive numbers 2k-49999994055005 is a prime.

It is a super-3 number, since 3×499999940550053 (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4999999405496 + ... + 4999999405505.

It is an arithmetic number, because the mean of its divisors is an integer number (14999998216503).

Almost surely, 249999994055005 is an apocalyptic number.

It is an amenable number.

49999994055005 is a deficient number, since it is larger than the sum of its proper divisors (9999998811007).

49999994055005 is an equidigital number, since it uses as much as digits as its factorization.

49999994055005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9999998811006.

The product of its (nonzero) digits is 1062882000, while the sum is 77.

The spelling of 49999994055005 in words is "forty-nine trillion, nine hundred ninety-nine billion, nine hundred ninety-four million, fifty-five thousand, five".

Divisors: 1 5 9999998811001 49999994055005