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500099074133 = 796330368027
BaseRepresentation
bin1110100011100000011…
…10100100100001010101
31202210211202122012101212
413101300032210201111
531143200330333013
61021424202431205
751062630664251
oct7216016444125
91683752565355
10500099074133
111830aa98734a
1280b0a202505
133820b829019
141a2c2453261
15d01e6a36a8
hex74703a4855

500099074133 has 4 divisors (see below), whose sum is σ = 506429442240. Its totient is φ = 493768706028.

The previous prime is 500099074091. The next prime is 500099074147. The reversal of 500099074133 is 331470990005.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 500099074133 - 222 = 500094879829 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (500099074193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3165183935 + ... + 3165184092.

It is an arithmetic number, because the mean of its divisors is an integer number (126607360560).

Almost surely, 2500099074133 is an apocalyptic number.

It is an amenable number.

500099074133 is a deficient number, since it is larger than the sum of its proper divisors (6330368107).

500099074133 is an equidigital number, since it uses as much as digits as its factorization.

500099074133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6330368106.

The product of its (nonzero) digits is 102060, while the sum is 41.

The spelling of 500099074133 in words is "five hundred billion, ninety-nine million, seventy-four thousand, one hundred thirty-three".

Divisors: 1 79 6330368027 500099074133