Base | Representation |
---|---|
bin | 101110100101000101… |
… | …011010101110011011 |
3 | 11210002120201202000121 |
4 | 232211011122232123 |
5 | 1304412130113313 |
6 | 34550512014111 |
7 | 3420254354605 |
oct | 564505325633 |
9 | 153076652017 |
10 | 50014301083 |
11 | 1a23585072a |
12 | 9839831337 |
13 | 4940a091c6 |
14 | 25c65b4175 |
15 | 147ac6c28d |
hex | ba515ab9b |
50014301083 has 4 divisors (see below), whose sum is σ = 51177424408. Its totient is φ = 48851177760.
The previous prime is 50014301063. The next prime is 50014301107. The reversal of 50014301083 is 38010341005.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50014301083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50014301033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 581561598 + ... + 581561683.
It is an arithmetic number, because the mean of its divisors is an integer number (12794356102).
Almost surely, 250014301083 is an apocalyptic number.
50014301083 is a deficient number, since it is larger than the sum of its proper divisors (1163123325).
50014301083 is a wasteful number, since it uses less digits than its factorization.
50014301083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1163123324.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 50014301083 its reverse (38010341005), we get a palindrome (88024642088).
The spelling of 50014301083 in words is "fifty billion, fourteen million, three hundred one thousand, eighty-three".
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