Base | Representation |
---|---|
bin | 100100011001110011000… |
… | …0010000010000101001011 |
3 | 122201022010200210012121101 |
4 | 1020303212002002011023 |
5 | 1123433024003200120 |
6 | 14350234445522231 |
7 | 1024316663503546 |
oct | 110634602020513 |
9 | 18638120705541 |
10 | 5003201225035 |
11 | 1659933727292 |
12 | 6897a1b73377 |
13 | 2a3a52371570 |
14 | 1342289ad85d |
15 | 8a2287b290a |
hex | 48ce608214b |
5003201225035 has 128 divisors (see below), whose sum is σ = 7163570534400. Its totient is φ = 3319070515200.
The previous prime is 5003201224999. The next prime is 5003201225129. The reversal of 5003201225035 is 5305221023005.
5003201225035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5003201225035 - 223 = 5003192836427 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5003201224994 and 5003201225012.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1970538796 + ... + 1970541334.
It is an arithmetic number, because the mean of its divisors is an integer number (55965394800).
Almost surely, 25003201225035 is an apocalyptic number.
5003201225035 is a deficient number, since it is larger than the sum of its proper divisors (2160369309365).
5003201225035 is a wasteful number, since it uses less digits than its factorization.
5003201225035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3173.
The product of its (nonzero) digits is 9000, while the sum is 28.
The spelling of 5003201225035 in words is "five trillion, three billion, two hundred one million, two hundred twenty-five thousand, thirty-five".
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