Base | Representation |
---|---|
bin | 10110110000101010011001… |
… | …10111100011000101011111 |
3 | 20120012210012102201122012212 |
4 | 23120111030313203011133 |
5 | 23030012003120432320 |
6 | 254240522520351035 |
7 | 13354014061351325 |
oct | 1330251467430537 |
9 | 216183172648185 |
10 | 50050543530335 |
11 | 14a4735300a567 |
12 | 574416991547b |
13 | 21c0990c7948a |
14 | c506601c1d15 |
15 | 5bbde20ba9c5 |
hex | 2d854cde315f |
50050543530335 has 4 divisors (see below), whose sum is σ = 60060652236408. Its totient is φ = 40040434824264.
The previous prime is 50050543530319. The next prime is 50050543530341. The reversal of 50050543530335 is 53303534505005.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50050543530335 - 24 = 50050543530319 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50050543530292 and 50050543530301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5005054353029 + ... + 5005054353038.
It is an arithmetic number, because the mean of its divisors is an integer number (15015163059102).
Almost surely, 250050543530335 is an apocalyptic number.
50050543530335 is a deficient number, since it is larger than the sum of its proper divisors (10010108706073).
50050543530335 is a wasteful number, since it uses less digits than its factorization.
50050543530335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10010108706072.
The product of its (nonzero) digits is 1012500, while the sum is 41.
The spelling of 50050543530335 in words is "fifty trillion, fifty billion, five hundred forty-three million, five hundred thirty thousand, three hundred thirty-five".
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