Base | Representation |
---|---|
bin | 10110110000110011101010… |
… | …11111010110101011110011 |
3 | 20120020021001020212120100122 |
4 | 23120121311133112223303 |
5 | 23030102201111134420 |
6 | 254243104412040455 |
7 | 13354251310003211 |
oct | 1330316537265363 |
9 | 216207036776318 |
10 | 50055520021235 |
11 | 14a4947711a863 |
12 | 574511846312b |
13 | 21c12a4c96651 |
14 | c509b30c3cb1 |
15 | 5bc0d3e2b725 |
hex | 2d86757d6af3 |
50055520021235 has 16 divisors (see below), whose sum is σ = 62705791808064. Its totient is φ = 38286502797312.
The previous prime is 50055520021217. The next prime is 50055520021249. The reversal of 50055520021235 is 53212002555005.
It is a cyclic number.
It is not a de Polignac number, because 50055520021235 - 232 = 50051225053939 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50055520021195 and 50055520021204.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95485502 + ... + 96008291.
It is an arithmetic number, because the mean of its divisors is an integer number (3919111988004).
Almost surely, 250055520021235 is an apocalyptic number.
50055520021235 is a deficient number, since it is larger than the sum of its proper divisors (12650271786829).
50055520021235 is a wasteful number, since it uses less digits than its factorization.
50055520021235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191496094.
The product of its (nonzero) digits is 75000, while the sum is 35.
The spelling of 50055520021235 in words is "fifty trillion, fifty-five billion, five hundred twenty million, twenty-one thousand, two hundred thirty-five".
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