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50055520021249 is a prime number
BaseRepresentation
bin10110110000110011101010…
…11111010110101100000001
320120020021001020212120101011
423120121311133112230001
523030102201111134444
6254243104412040521
713354251310003231
oct1330316537265401
9216207036776334
1050055520021249
1114a4947711a876
125745118463141
1321c12a4c96662
14c509b30c3cc1
155bc0d3e2b734
hex2d86757d6b01

50055520021249 has 2 divisors, whose sum is σ = 50055520021250. Its totient is φ = 50055520021248.

The previous prime is 50055520021217. The next prime is 50055520021313. The reversal of 50055520021249 is 94212002555005.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 45611990932225 + 4443529089024 = 6753665^2 + 2107968^2 .

It is a cyclic number.

It is not a de Polignac number, because 50055520021249 - 25 = 50055520021217 is a prime.

It is not a weakly prime, because it can be changed into another prime (50055520024249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25027760010624 + 25027760010625.

It is an arithmetic number, because the mean of its divisors is an integer number (25027760010625).

Almost surely, 250055520021249 is an apocalyptic number.

It is an amenable number.

50055520021249 is a deficient number, since it is larger than the sum of its proper divisors (1).

50055520021249 is an equidigital number, since it uses as much as digits as its factorization.

50055520021249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

The spelling of 50055520021249 in words is "fifty trillion, fifty-five billion, five hundred twenty million, twenty-one thousand, two hundred forty-nine".