Base | Representation |
---|---|
bin | 100100011011110001100… |
… | …0111000010001010000001 |
3 | 122201201002121021122110202 |
4 | 1020313203013002022001 |
5 | 1124020222433443323 |
6 | 14352220043134545 |
7 | 1024530131451050 |
oct | 110674307021201 |
9 | 18651077248422 |
10 | 5007447171713 |
11 | 1660712425928 |
12 | 68a587b14455 |
13 | 2a427ac1674c |
14 | 13450c866397 |
15 | 8a3c641ad28 |
hex | 48de31c2281 |
5007447171713 has 4 divisors (see below), whose sum is σ = 5722796767680. Its totient is φ = 4292097575748.
The previous prime is 5007447171697. The next prime is 5007447171721. The reversal of 5007447171713 is 3171717447005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5007447171713 - 24 = 5007447171697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5007447171733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357674797973 + ... + 357674797986.
It is an arithmetic number, because the mean of its divisors is an integer number (1430699191920).
Almost surely, 25007447171713 is an apocalyptic number.
It is an amenable number.
5007447171713 is a deficient number, since it is larger than the sum of its proper divisors (715349595967).
5007447171713 is an equidigital number, since it uses as much as digits as its factorization.
5007447171713 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 715349595966.
The product of its (nonzero) digits is 576240, while the sum is 47.
The spelling of 5007447171713 in words is "five trillion, seven billion, four hundred forty-seven million, one hundred seventy-one thousand, seven hundred thirteen".
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