Base | Representation |
---|---|
bin | 101110101001001100… |
… | …111111001010000001 |
3 | 11210021101202000221002 |
4 | 232221030333022001 |
5 | 1310032322103202 |
6 | 35001420541345 |
7 | 3422053553315 |
oct | 565114771201 |
9 | 153241660832 |
10 | 50083394177 |
11 | 1a270852363 |
12 | 98589b1855 |
13 | 495211acab |
14 | 25d183bb45 |
15 | 1481d69302 |
hex | ba933f281 |
50083394177 has 4 divisors (see below), whose sum is σ = 50087353860. Its totient is φ = 50079434496.
The previous prime is 50083394173. The next prime is 50083394201. The reversal of 50083394177 is 77149338005.
50083394177 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 21800227201 + 28283166976 = 147649^2 + 168176^2 .
It is a cyclic number.
It is not a de Polignac number, because 50083394177 - 22 = 50083394173 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50083394173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1960808 + ... + 1986185.
It is an arithmetic number, because the mean of its divisors is an integer number (12521838465).
Almost surely, 250083394177 is an apocalyptic number.
It is an amenable number.
50083394177 is a deficient number, since it is larger than the sum of its proper divisors (3959683).
50083394177 is a wasteful number, since it uses less digits than its factorization.
50083394177 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3959682.
The product of its (nonzero) digits is 635040, while the sum is 47.
The spelling of 50083394177 in words is "fifty billion, eighty-three million, three hundred ninety-four thousand, one hundred seventy-seven".
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