Base | Representation |
---|---|
bin | 101110101010010100… |
… | …001000011100011001 |
3 | 11210022200211120021121 |
4 | 232222110020130121 |
5 | 1310102110410231 |
6 | 35003324405241 |
7 | 3422401231261 |
oct | 565224103431 |
9 | 153280746247 |
10 | 50102044441 |
11 | 1a2803305a9 |
12 | 98630a6821 |
13 | 4955c4ac57 |
14 | 25d40d47a1 |
15 | 1483800311 |
hex | baa508719 |
50102044441 has 4 divisors (see below), whose sum is σ = 50103703332. Its totient is φ = 50100385552.
The previous prime is 50102044427. The next prime is 50102044453. The reversal of 50102044441 is 14444020105.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14444020105 = 5 ⋅2888804021.
It can be written as a sum of positive squares in 2 ways, for example, as 30135224025 + 19966820416 = 173595^2 + 141304^2 .
It is a cyclic number.
It is not a de Polignac number, because 50102044441 - 25 = 50102044409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50102044481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783286 + ... + 844831.
It is an arithmetic number, because the mean of its divisors is an integer number (12525925833).
Almost surely, 250102044441 is an apocalyptic number.
It is an amenable number.
50102044441 is a deficient number, since it is larger than the sum of its proper divisors (1658891).
50102044441 is a wasteful number, since it uses less digits than its factorization.
50102044441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1658890.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 50102044441 its reverse (14444020105), we get a palindrome (64546064546).
The spelling of 50102044441 in words is "fifty billion, one hundred two million, forty-four thousand, four hundred forty-one".
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