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50112030103 = 211237497773
BaseRepresentation
bin101110101010111010…
…001110010110010111
311210100101121220000221
4232222322032112113
51310112134430403
635004322415211
73422552141062
oct565272162627
9153311556027
1050112030103
111a285a30a13
129866501507
134958036125
1425d55738d9
151484623dbd
hexbaae8e597

50112030103 has 4 divisors (see below), whose sum is σ = 50349528088. Its totient is φ = 49874532120.

The previous prime is 50112030083. The next prime is 50112030119. The reversal of 50112030103 is 30103021105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50112030103 - 25 = 50112030071 is a prime.

It is a super-2 number, since 2×501120301032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50112030173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118748676 + ... + 118749097.

It is an arithmetic number, because the mean of its divisors is an integer number (12587382022).

Almost surely, 250112030103 is an apocalyptic number.

50112030103 is a deficient number, since it is larger than the sum of its proper divisors (237497985).

50112030103 is a wasteful number, since it uses less digits than its factorization.

50112030103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237497984.

The product of its (nonzero) digits is 90, while the sum is 16.

Adding to 50112030103 its reverse (30103021105), we get a palindrome (80215051208).

The spelling of 50112030103 in words is "fifty billion, one hundred twelve million, thirty thousand, one hundred three".

Divisors: 1 211 237497773 50112030103