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50112425143 = 114555675013
BaseRepresentation
bin101110101010111011…
…101110110010110111
311210100102100221221001
4232222323232302313
51310112240101033
635004335104131
73422555404564
oct565273566267
9153312327831
1050112425143
111a2861807a0
129866672047
134958143b91
1425d563786b
1514846a0e7d
hexbaaeeecb7

50112425143 has 4 divisors (see below), whose sum is σ = 54668100168. Its totient is φ = 45556750120.

The previous prime is 50112425131. The next prime is 50112425147. The reversal of 50112425143 is 34152421105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50112425143 is a prime.

It is a super-2 number, since 2×501124251432 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50112425147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2277837496 + ... + 2277837517.

It is an arithmetic number, because the mean of its divisors is an integer number (13667025042).

Almost surely, 250112425143 is an apocalyptic number.

50112425143 is a deficient number, since it is larger than the sum of its proper divisors (4555675025).

50112425143 is a wasteful number, since it uses less digits than its factorization.

50112425143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4555675024.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 50112425143 its reverse (34152421105), we get a palindrome (84264846248).

The spelling of 50112425143 in words is "fifty billion, one hundred twelve million, four hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 11 4555675013 50112425143