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50113053143 = 1011709290327
BaseRepresentation
bin101110101010111110…
…001000000111010111
311210100110112212101022
4232222332020013113
51310112420200033
635004400351355
73422563631516
oct565276100727
9153313485338
1050113053143
111a28656a5aa
12986691555b
13495830398a
1425d575c67d
151484777098
hexbaaf881d7

50113053143 has 8 divisors (see below), whose sum is σ = 50639009760. Its totient is φ = 49587680800.

The previous prime is 50113053127. The next prime is 50113053167. The reversal of 50113053143 is 34135031105.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50113053143 - 24 = 50113053127 is a prime.

It is a super-2 number, since 2×501130531432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50113053103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27446 + ... + 317772.

It is an arithmetic number, because the mean of its divisors is an integer number (6329876220).

Almost surely, 250113053143 is an apocalyptic number.

50113053143 is a deficient number, since it is larger than the sum of its proper divisors (525956617).

50113053143 is a wasteful number, since it uses less digits than its factorization.

50113053143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 292137.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 50113053143 its reverse (34135031105), we get a palindrome (84248084248).

The spelling of 50113053143 in words is "fifty billion, one hundred thirteen million, fifty-three thousand, one hundred forty-three".

Divisors: 1 101 1709 172609 290327 29323027 496168843 50113053143