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50113435979 = 108746102517
BaseRepresentation
bin101110101010111111…
…100101100101001011
311210100111021022112102
4232222333211211023
51310113014422404
635004412504015
73422600114615
oct565277454513
9153314238472
1050113435979
111a2868011a2
129866a7b00b
134958408cc9
1425d581bdb5
15148480071e
hexbaafe594b

50113435979 has 4 divisors (see below), whose sum is σ = 50159539584. Its totient is φ = 50067332376.

The previous prime is 50113435961. The next prime is 50113436039. The reversal of 50113435979 is 97953431105.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 97953431105 = 519590686221.

It is a cyclic number.

It is not a de Polignac number, because 50113435979 - 228 = 49845000523 is a prime.

It is a super-2 number, since 2×501134359792 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50113455979) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23050172 + ... + 23052345.

It is an arithmetic number, because the mean of its divisors is an integer number (12539884896).

Almost surely, 250113435979 is an apocalyptic number.

50113435979 is a deficient number, since it is larger than the sum of its proper divisors (46103605).

50113435979 is a wasteful number, since it uses less digits than its factorization.

50113435979 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46103604.

The product of its (nonzero) digits is 510300, while the sum is 47.

The spelling of 50113435979 in words is "fifty billion, one hundred thirteen million, four hundred thirty-five thousand, nine hundred seventy-nine".

Divisors: 1 1087 46102517 50113435979