Base | Representation |
---|---|
bin | 10110110010100011000001… |
… | …01011011110101000110111 |
3 | 20120102222100110020111001101 |
4 | 23121101200223132220313 |
5 | 23032042113401421101 |
6 | 254330352353310531 |
7 | 13361465602005421 |
oct | 1331214053365067 |
9 | 216388313214041 |
10 | 50115300420151 |
11 | 14a7186364731a |
12 | 5754820865447 |
13 | 21c6b11095865 |
14 | c53844731811 |
15 | 5bd932252401 |
hex | 2d9460adea37 |
50115300420151 has 4 divisors (see below), whose sum is σ = 51469767999112. Its totient is φ = 48760832841192.
The previous prime is 50115300420019. The next prime is 50115300420181. The reversal of 50115300420151 is 15102400351105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50115300420151 - 219 = 50115299895863 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50115300420181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677233789425 + ... + 677233789498.
It is an arithmetic number, because the mean of its divisors is an integer number (12867441999778).
Almost surely, 250115300420151 is an apocalyptic number.
50115300420151 is a deficient number, since it is larger than the sum of its proper divisors (1354467578961).
50115300420151 is a wasteful number, since it uses less digits than its factorization.
50115300420151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1354467578960.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 50115300420151 its reverse (15102400351105), we get a palindrome (65217700771256).
The spelling of 50115300420151 in words is "fifty trillion, one hundred fifteen billion, three hundred million, four hundred twenty thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •