Base | Representation |
---|---|
bin | 10110110010111000010101… |
… | …00111010010000011101001 |
3 | 20120111001212210102112100011 |
4 | 23121130022213102003221 |
5 | 23032234031243200403 |
6 | 254335523533011521 |
7 | 13362352244403430 |
oct | 1331341247220351 |
9 | 216431783375304 |
10 | 50126741381353 |
11 | 14a766a478785a |
12 | 5756a94323ba1 |
13 | 21c7c154739a0 |
14 | c5420bdca117 |
15 | 5bdda1896a6d |
hex | 2d970a9d20e9 |
50126741381353 has 64 divisors (see below), whose sum is σ = 67087027732480. Its totient is φ = 36333817228800.
The previous prime is 50126741381347. The next prime is 50126741381399. The reversal of 50126741381353 is 35318314762105.
It is a de Polignac number, because none of the positive numbers 2k-50126741381353 is a prime.
It is a super-2 number, since 2×501267413813532 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50126741381297 and 50126741381306.
It is not an unprimeable number, because it can be changed into a prime (50126741381323) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 70773493 + ... + 71478253.
It is an arithmetic number, because the mean of its divisors is an integer number (1048234808320).
Almost surely, 250126741381353 is an apocalyptic number.
It is an amenable number.
50126741381353 is a deficient number, since it is larger than the sum of its proper divisors (16960286351127).
50126741381353 is a wasteful number, since it uses less digits than its factorization.
50126741381353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 706158.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 50126741381353 in words is "fifty trillion, one hundred twenty-six billion, seven hundred forty-one million, three hundred eighty-one thousand, three hundred fifty-three".
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