Base | Representation |
---|---|
bin | 100100011110011110111… |
… | …1000110100000101110001 |
3 | 122202021010001210221212211 |
4 | 1020330331320310011301 |
5 | 1124114131333404113 |
6 | 14355021234252121 |
7 | 1025124245401015 |
oct | 110747570640561 |
9 | 18667101727784 |
10 | 5013265138033 |
11 | 1663128525059 |
12 | 68b730427041 |
13 | 2a4997378a79 |
14 | 13490140c545 |
15 | 8a617097b3d |
hex | 48f3de34171 |
5013265138033 has 4 divisors (see below), whose sum is σ = 5014423743040. Its totient is φ = 5012106533028.
The previous prime is 5013265138027. The next prime is 5013265138039. The reversal of 5013265138033 is 3308315623105.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (5013265138027) and next prime (5013265138039).
It is a cyclic number.
It is not a de Polignac number, because 5013265138033 - 25 = 5013265138001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5013265138039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 579296013 + ... + 579304666.
It is an arithmetic number, because the mean of its divisors is an integer number (1253605935760).
Almost surely, 25013265138033 is an apocalyptic number.
It is an amenable number.
5013265138033 is a deficient number, since it is larger than the sum of its proper divisors (1158605007).
5013265138033 is a wasteful number, since it uses less digits than its factorization.
5013265138033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1158605006.
The product of its (nonzero) digits is 194400, while the sum is 40.
The spelling of 5013265138033 in words is "five trillion, thirteen billion, two hundred sixty-five million, one hundred thirty-eight thousand, thirty-three".
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