Base | Representation |
---|---|
bin | 10110110011000100101001… |
… | …01110100001100110101001 |
3 | 20120111200221121022010020212 |
4 | 23121202110232201212221 |
5 | 23032341101444100040 |
6 | 254342540013430505 |
7 | 13363005143455433 |
oct | 1331422456414651 |
9 | 216450847263225 |
10 | 50133353503145 |
11 | 14a79488095820 |
12 | 575821a79b435 |
13 | 21c872a2c08a3 |
14 | c54678219653 |
15 | 5be13c0e3d65 |
hex | 2d9894ba19a9 |
50133353503145 has 32 divisors (see below), whose sum is σ = 67404592354176. Its totient is φ = 35474295859200.
The previous prime is 50133353503141. The next prime is 50133353503159. The reversal of 50133353503145 is 54130535333105.
It is not a de Polignac number, because 50133353503145 - 22 = 50133353503141 is a prime.
It is not an unprimeable number, because it can be changed into a prime (50133353503141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 85444217 + ... + 86028953.
It is an arithmetic number, because the mean of its divisors is an integer number (2106393511068).
Almost surely, 250133353503145 is an apocalyptic number.
50133353503145 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
50133353503145 is a deficient number, since it is larger than the sum of its proper divisors (17271238851031).
50133353503145 is a wasteful number, since it uses less digits than its factorization.
50133353503145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 626921.
The product of its (nonzero) digits is 607500, while the sum is 41.
The spelling of 50133353503145 in words is "fifty trillion, one hundred thirty-three billion, three hundred fifty-three million, five hundred three thousand, one hundred forty-five".
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