Base | Representation |
---|---|
bin | 10110110011011110010010… |
… | …11001100011011110111001 |
3 | 20120120000111011100022121012 |
4 | 23121233021121203132321 |
5 | 23033102301224201103 |
6 | 254353134142323305 |
7 | 13364003301555611 |
oct | 1331571131433671 |
9 | 216500434308535 |
10 | 50147122100153 |
11 | 14a84303102511 |
12 | 575aa21889535 |
13 | 21c9b1299ba00 |
14 | c551c2a97a41 |
15 | 5be695c682d8 |
hex | 2d9bc96637b9 |
50147122100153 has 12 divisors (see below), whose sum is σ = 54301684138128. Its totient is φ = 46289342090160.
The previous prime is 50147122100147. The next prime is 50147122100161. The reversal of 50147122100153 is 35100122174105.
It is not a de Polignac number, because 50147122100153 - 24 = 50147122100137 is a prime.
It is a super-4 number, since 4×501471221001534 (a number of 56 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50147122100123) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26673626 + ... + 28491692.
It is an arithmetic number, because the mean of its divisors is an integer number (4525140344844).
Almost surely, 250147122100153 is an apocalyptic number.
It is an amenable number.
50147122100153 is a deficient number, since it is larger than the sum of its proper divisors (4154562037975).
50147122100153 is a wasteful number, since it uses less digits than its factorization.
50147122100153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1981304 (or 1981291 counting only the distinct ones).
The product of its (nonzero) digits is 8400, while the sum is 32.
Adding to 50147122100153 its reverse (35100122174105), we get a palindrome (85247244274258).
The spelling of 50147122100153 in words is "fifty trillion, one hundred forty-seven billion, one hundred twenty-two million, one hundred thousand, one hundred fifty-three".
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