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5015342131003 = 25119981442753
BaseRepresentation
bin100100011111011100110…
…1011111010011100111011
3122202110110211001010121101
41020332321223322130323
51124132410041143003
614400003311352231
71025226565503061
oct110767153723473
918673424033541
105015342131003
111663aa3979676
1269000bb22677
132a4c3876c8a9
14134a5b1ca031
158a6d95b811d
hex48fb9afa73b

5015342131003 has 4 divisors (see below), whose sum is σ = 5035323574008. Its totient is φ = 4995360688000.

The previous prime is 5015342130979. The next prime is 5015342131013. The reversal of 5015342131003 is 3001312435105.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5015342131003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5015342131013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9990721126 + ... + 9990721627.

It is an arithmetic number, because the mean of its divisors is an integer number (1258830893502).

Almost surely, 25015342131003 is an apocalyptic number.

5015342131003 is a deficient number, since it is larger than the sum of its proper divisors (19981443005).

5015342131003 is a wasteful number, since it uses less digits than its factorization.

5015342131003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19981443004.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 5015342131003 its reverse (3001312435105), we get a palindrome (8016654566108).

The spelling of 5015342131003 in words is "five trillion, fifteen billion, three hundred forty-two million, one hundred thirty-one thousand, three".

Divisors: 1 251 19981442753 5015342131003