Base | Representation |
---|---|
bin | 100100011111011101000… |
… | …1010000101011001001111 |
3 | 122202110111100220221220111 |
4 | 1020332322022011121033 |
5 | 1124132414102241033 |
6 | 14400004153100451 |
7 | 1025230022643562 |
oct | 110767212053117 |
9 | 18673440827814 |
10 | 5015350040143 |
11 | 1663aa8390953 |
12 | 6900126b7727 |
13 | 2a4c3a2ab861 |
14 | 134a5c2884d9 |
15 | 8a6da12b7cd |
hex | 48fba28564f |
5015350040143 has 4 divisors (see below), whose sum is σ = 5028444949248. Its totient is φ = 5002255131040.
The previous prime is 5015350040083. The next prime is 5015350040147. The reversal of 5015350040143 is 3410400535105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5015350040143 - 29 = 5015350039631 is a prime.
It is a super-2 number, since 2×50153500401432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5015350040147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6547453978 + ... + 6547454743.
It is an arithmetic number, because the mean of its divisors is an integer number (1257111237312).
Almost surely, 25015350040143 is an apocalyptic number.
5015350040143 is a deficient number, since it is larger than the sum of its proper divisors (13094909105).
5015350040143 is a wasteful number, since it uses less digits than its factorization.
5015350040143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13094909104.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 5015350040143 its reverse (3410400535105), we get a palindrome (8425750575248).
The spelling of 5015350040143 in words is "five trillion, fifteen billion, three hundred fifty million, forty thousand, one hundred forty-three".
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