Base | Representation |
---|---|
bin | 1001010101111101… |
… | …11101010011100011 |
3 | 110221120201000100221 |
4 | 10222332331103203 |
5 | 40233111130103 |
6 | 2145424423511 |
7 | 235206161146 |
oct | 45276752343 |
9 | 13846630327 |
10 | 5016114403 |
11 | 2144513aa3 |
12 | b7ba77b97 |
13 | 61c2b1541 |
14 | 35829805d |
15 | 1e558b1bd |
hex | 12afbd4e3 |
5016114403 has 4 divisors (see below), whose sum is σ = 5027286600. Its totient is φ = 5004942208.
The previous prime is 5016114391. The next prime is 5016114449. The reversal of 5016114403 is 3044116105.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3044116105 = 5 ⋅608823221.
It is a cyclic number.
It is not a de Polignac number, because 5016114403 - 221 = 5014017251 is a prime.
It is a super-2 number, since 2×50161144032 = 50322807407968092818, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5016114463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5585425 + ... + 5586322.
It is an arithmetic number, because the mean of its divisors is an integer number (1256821650).
Almost surely, 25016114403 is an apocalyptic number.
5016114403 is a deficient number, since it is larger than the sum of its proper divisors (11172197).
5016114403 is a wasteful number, since it uses less digits than its factorization.
5016114403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11172196.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 5016114403 is about 70824.5324940447. The cubic root of 5016114403 is about 1711.8109928098.
The spelling of 5016114403 in words is "five billion, sixteen million, one hundred fourteen thousand, four hundred three".
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