Base | Representation |
---|---|
bin | 101110101101111111… |
… | …110100110101100001 |
3 | 11210111000002121021211 |
4 | 232231333310311201 |
5 | 1310213420030423 |
6 | 35013412550121 |
7 | 3424051343365 |
oct | 565577646541 |
9 | 153430077254 |
10 | 50163830113 |
11 | 1a3021a1041 |
12 | 987b922341 |
13 | 49659a1917 |
14 | 25dc3b92a5 |
15 | 1488e5710d |
hex | badff4d61 |
50163830113 has 4 divisors (see below), whose sum is σ = 50164888240. Its totient is φ = 50162771988.
The previous prime is 50163830099. The next prime is 50163830137. The reversal of 50163830113 is 31103836105.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31103836105 = 5 ⋅6220767221.
It is a cyclic number.
It is not a de Polignac number, because 50163830113 - 213 = 50163821921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50163830713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 454443 + ... + 553936.
It is an arithmetic number, because the mean of its divisors is an integer number (12541222060).
Almost surely, 250163830113 is an apocalyptic number.
It is an amenable number.
50163830113 is a deficient number, since it is larger than the sum of its proper divisors (1058127).
50163830113 is a wasteful number, since it uses less digits than its factorization.
50163830113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1058126.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 50163830113 in words is "fifty billion, one hundred sixty-three million, eight hundred thirty thousand, one hundred thirteen".
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