Base | Representation |
---|---|
bin | 10110110100011010001001… |
… | …00111111100100001111111 |
3 | 20120200002102111122012220220 |
4 | 23122031010213330201333 |
5 | 23034114103041211112 |
6 | 254420010421512423 |
7 | 13366221461345664 |
oct | 1332150447744177 |
9 | 216602374565826 |
10 | 50179254241407 |
11 | 14a969a1937855 |
12 | 57650aa872713 |
13 | 21ccb639c6445 |
14 | c56990357a6b |
15 | 5c0426b5798c |
hex | 2da3449fc87f |
50179254241407 has 4 divisors (see below), whose sum is σ = 66905672321880. Its totient is φ = 33452836160936.
The previous prime is 50179254241397. The next prime is 50179254241433. The reversal of 50179254241407 is 70414245297105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50179254241407 - 242 = 45781207730303 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50179254241407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50179254241007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8363209040232 + ... + 8363209040237.
It is an arithmetic number, because the mean of its divisors is an integer number (16726418080470).
Almost surely, 250179254241407 is an apocalyptic number.
50179254241407 is a deficient number, since it is larger than the sum of its proper divisors (16726418080473).
50179254241407 is a wasteful number, since it uses less digits than its factorization.
50179254241407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16726418080472.
The product of its (nonzero) digits is 2822400, while the sum is 51.
The spelling of 50179254241407 in words is "fifty trillion, one hundred seventy-nine billion, two hundred fifty-four million, two hundred forty-one thousand, four hundred seven".
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