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50201311203 = 3253105243839
BaseRepresentation
bin101110110000001110…
…110011011111100011
311210120121121211200100
4232300032303133203
51310303013424303
635021232153443
73425015050611
oct566016633743
9153517554610
1050201311203
111a32137114a
129890398883
134970695a94
1426033746b1
15148c3ac8a3
hexbb03b37e3

50201311203 has 12 divisors (see below), whose sum is σ = 73881175680. Its totient is φ = 32836077456.

The previous prime is 50201311201. The next prime is 50201311211. The reversal of 50201311203 is 30211310205.

It is not a de Polignac number, because 50201311203 - 21 = 50201311201 is a prime.

It is a super-3 number, since 3×502013112033 (a number of 33 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (50201311201) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 52621443 + ... + 52622396.

It is an arithmetic number, because the mean of its divisors is an integer number (6156764640).

Almost surely, 250201311203 is an apocalyptic number.

50201311203 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

50201311203 is a deficient number, since it is larger than the sum of its proper divisors (23679864477).

50201311203 is a wasteful number, since it uses less digits than its factorization.

50201311203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105243898 (or 105243895 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 18.

Adding to 50201311203 its reverse (30211310205), we get a palindrome (80412621408).

The spelling of 50201311203 in words is "fifty billion, two hundred one million, three hundred eleven thousand, two hundred three".

Divisors: 1 3 9 53 159 477 105243839 315731517 947194551 5577923467 16733770401 50201311203