Base | Representation |
---|---|
bin | 100100100001110001110… |
… | …1101011111001110000001 |
3 | 122202221101021110121212111 |
4 | 1021003203231133032001 |
5 | 1124223130042412423 |
6 | 14402151403255321 |
7 | 1025464521134656 |
oct | 111034355371601 |
9 | 18687337417774 |
10 | 5020342154113 |
11 | 166612a2a1a80 |
12 | 690b8651a541 |
13 | 2a5554608b50 |
14 | 134db3295c2d |
15 | 8a8cd52660d |
hex | 490e3b5f381 |
5020342154113 has 32 divisors (see below), whose sum is σ = 6478379228160. Its totient is φ = 3817616235840.
The previous prime is 5020342154101. The next prime is 5020342154147. The reversal of 5020342154113 is 3114512430205.
It is not a de Polignac number, because 5020342154113 - 221 = 5020340056961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5020342158113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40106031 + ... + 40231012.
It is an arithmetic number, because the mean of its divisors is an integer number (202449350880).
Almost surely, 25020342154113 is an apocalyptic number.
It is an amenable number.
5020342154113 is a deficient number, since it is larger than the sum of its proper divisors (1458037074047).
5020342154113 is a wasteful number, since it uses less digits than its factorization.
5020342154113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80337109.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 5020342154113 its reverse (3114512430205), we get a palindrome (8134854584318).
The spelling of 5020342154113 in words is "five trillion, twenty billion, three hundred forty-two million, one hundred fifty-four thousand, one hundred thirteen".
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