Base | Representation |
---|---|
bin | 100100100010001111011… |
… | …0110101111011000000111 |
3 | 122210000221102121201210212 |
4 | 1021010132312233120013 |
5 | 1124232143103412320 |
6 | 14402434051310035 |
7 | 1025531230320101 |
oct | 111043666573007 |
9 | 18700842551725 |
10 | 5021334435335 |
11 | 16665994235a9 |
12 | 6912028ab31b |
13 | 2a56820728ba |
14 | 135068d94571 |
15 | 8a93a6d09c5 |
hex | 4911edaf607 |
5021334435335 has 16 divisors (see below), whose sum is σ = 6107863587840. Its totient is φ = 3962379445920.
The previous prime is 5021334435287. The next prime is 5021334435367. The reversal of 5021334435335 is 5335344331205.
It is not a de Polignac number, because 5021334435335 - 214 = 5021334418951 is a prime.
It is a super-2 number, since 2×50213344353352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5021334435292 and 5021334435301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9325775 + ... + 9849504.
It is an arithmetic number, because the mean of its divisors is an integer number (381741474240).
Almost surely, 25021334435335 is an apocalyptic number.
5021334435335 is a deficient number, since it is larger than the sum of its proper divisors (1086529152505).
5021334435335 is a wasteful number, since it uses less digits than its factorization.
5021334435335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19175998.
The product of its (nonzero) digits is 972000, while the sum is 41.
The spelling of 5021334435335 in words is "five trillion, twenty-one billion, three hundred thirty-four million, four hundred thirty-five thousand, three hundred thirty-five".
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