Search a number
-
+
5022525113131 = 28117873754851
BaseRepresentation
bin100100100010110010111…
…0100110100001100101011
3122210011000102002102200111
41021011211310310030223
51124242112412110011
614403152143515151
71025602566030661
oct111054564641453
918704012072614
105022525113131
11166704a542439
126914955b8ab7
132a5811951b86
1413513d178c31
158a9a9ec9121
hex49165d3432b

5022525113131 has 4 divisors (see below), whose sum is σ = 5040398868264. Its totient is φ = 5004651358000.

The previous prime is 5022525113069. The next prime is 5022525113159. The reversal of 5022525113131 is 1313115252205.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5022525113131 - 225 = 5022491558699 is a prime.

It is a super-2 number, since 2×50225251131312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5022525113093 and 5022525113102.

It is not an unprimeable number, because it can be changed into a prime (5022525113831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8936877145 + ... + 8936877706.

It is an arithmetic number, because the mean of its divisors is an integer number (1260099717066).

Almost surely, 25022525113131 is an apocalyptic number.

5022525113131 is a deficient number, since it is larger than the sum of its proper divisors (17873755133).

5022525113131 is a wasteful number, since it uses less digits than its factorization.

5022525113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17873755132.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 5022525113131 in words is "five trillion, twenty-two billion, five hundred twenty-five million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 281 17873754851 5022525113131