Base | Representation |
---|---|
bin | 101110110110111001… |
… | …110100110101010101 |
3 | 11210212102021000211111 |
4 | 232312321310311111 |
5 | 1311020143032211 |
6 | 35040311335021 |
7 | 3430544405263 |
oct | 566671646525 |
9 | 153772230744 |
10 | 50313252181 |
11 | 1a379579055 |
12 | 9901981471 |
13 | 498a92a74a |
14 | 2614193433 |
15 | 1497120421 |
hex | bb6e74d55 |
50313252181 has 4 divisors (see below), whose sum is σ = 50409453952. Its totient is φ = 50217050412.
The previous prime is 50313252179. The next prime is 50313252251. The reversal of 50313252181 is 18125231305.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50313252181 - 21 = 50313252179 is a prime.
It is a super-2 number, since 2×503132521812 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50313252481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48100101 + ... + 48101146.
It is an arithmetic number, because the mean of its divisors is an integer number (12602363488).
Almost surely, 250313252181 is an apocalyptic number.
It is an amenable number.
50313252181 is a deficient number, since it is larger than the sum of its proper divisors (96201771).
50313252181 is an equidigital number, since it uses as much as digits as its factorization.
50313252181 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96201770.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 50313252181 its reverse (18125231305), we get a palindrome (68438483486).
The spelling of 50313252181 in words is "fifty billion, three hundred thirteen million, two hundred fifty-two thousand, one hundred eighty-one".
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