Base | Representation |
---|---|
bin | 100100100110111001011… |
… | …0001001101001111011111 |
3 | 122210222202012012002020001 |
4 | 1021031302301031033133 |
5 | 1124413132021034120 |
6 | 14411210114235131 |
7 | 1026334050054136 |
oct | 111156261151737 |
9 | 18728665162201 |
10 | 5031332205535 |
11 | 166a8599552a9 |
12 | 693132b85aa7 |
13 | 2a65b645c15c |
14 | 135736ad691d |
15 | 8ad2329ce0a |
hex | 49372c4d3df |
5031332205535 has 8 divisors (see below), whose sum is σ = 6037672299120. Its totient is φ = 4025016662784.
The previous prime is 5031332205469. The next prime is 5031332205539. The reversal of 5031332205535 is 5355022331305.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5031332205535 - 241 = 2832308949983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5031332205494 and 5031332205503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5031332205539) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5683797 + ... + 6509086.
It is an arithmetic number, because the mean of its divisors is an integer number (754709037390).
Almost surely, 25031332205535 is an apocalyptic number.
5031332205535 is a deficient number, since it is larger than the sum of its proper divisors (1006340093585).
5031332205535 is a wasteful number, since it uses less digits than its factorization.
5031332205535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12275417.
The product of its (nonzero) digits is 202500, while the sum is 37.
The spelling of 5031332205535 in words is "five trillion, thirty-one billion, three hundred thirty-two million, two hundred five thousand, five hundred thirty-five".
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