503311514054113 has 4 divisors (see below), whose sum is σ = 515016432985648. Its totient is φ = 491606595122580.

The previous prime is 503311514054057. The next prime is 503311514054161. The reversal of 503311514054113 is 311450415113305.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 503311514054113 - 2²¹ = 503311511956961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (503311514064113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5852459465703 + ... + 5852459465788.

It is an arithmetic number, because the mean of its divisors is an integer number (128754108246412).

Almost surely, 2^{503311514054113} is an apocalyptic number.

It is an amenable number.

503311514054113 is a deficient number, since it is larger than the sum of its proper divisors (11704918931535).

503311514054113 is a wasteful number, since it uses less digits than its factorization.

503311514054113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11704918931534.

The product of its (nonzero) digits is 54000, while the sum is 37.

Adding to 503311514054113 its reverse (311450415113305), we get a palindrome (814761929167418).

The spelling of 503311514054113 in words is "five hundred three trillion, three hundred eleven billion, five hundred fourteen million, fifty-four thousand, one hundred thirteen".