Base | Representation |
---|---|
bin | 100100100111110010010… |
… | …0100010100110001101111 |
3 | 122211011200020201210101220 |
4 | 1021033210210110301233 |
5 | 1124431034301244101 |
6 | 14412123355434423 |
7 | 1026432262156443 |
oct | 111174444246157 |
9 | 18734606653356 |
10 | 5033241431151 |
11 | 167064963180a |
12 | 693586455a13 |
13 | 2a682bb72c5b |
14 | 1358784c2823 |
15 | 8add5bce636 |
hex | 493e4914c6f |
5033241431151 has 8 divisors (see below), whose sum is σ = 6712191067824. Its totient is φ = 3354893040960.
The previous prime is 5033241431147. The next prime is 5033241431161. The reversal of 5033241431151 is 1511341423305.
5033241431151 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5033241431151 - 22 = 5033241431147 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5033241431111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150292086 + ... + 150325571.
It is an arithmetic number, because the mean of its divisors is an integer number (839023883478).
Almost surely, 25033241431151 is an apocalyptic number.
5033241431151 is a deficient number, since it is larger than the sum of its proper divisors (1678949636673).
5033241431151 is a wasteful number, since it uses less digits than its factorization.
5033241431151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300623241.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 5033241431151 its reverse (1511341423305), we get a palindrome (6544582854456).
The spelling of 5033241431151 in words is "five trillion, thirty-three billion, two hundred forty-one million, four hundred thirty-one thousand, one hundred fifty-one".
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