Base | Representation |
---|---|
bin | 100100100111110010100… |
… | …0101010011110101010011 |
3 | 122211011200212000002200212 |
4 | 1021033211011103311103 |
5 | 1124431044004444120 |
6 | 14412124305034335 |
7 | 1026432425522144 |
oct | 111174505236523 |
9 | 18734625002625 |
10 | 5033250078035 |
11 | 16706534a82a3 |
12 | 6935893259ab |
13 | 2a68308ac95a |
14 | 1358796d3acb |
15 | 8add683b6c5 |
hex | 493e5153d53 |
5033250078035 has 4 divisors (see below), whose sum is σ = 6039900093648. Its totient is φ = 4026600062424.
The previous prime is 5033250078029. The next prime is 5033250078047. The reversal of 5033250078035 is 5308700523305.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5033250078035 - 212 = 5033250073939 is a prime.
It is a super-2 number, since 2×50332500780352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5033250077983 and 5033250078001.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503325007799 + ... + 503325007808.
It is an arithmetic number, because the mean of its divisors is an integer number (1509975023412).
Almost surely, 25033250078035 is an apocalyptic number.
5033250078035 is a deficient number, since it is larger than the sum of its proper divisors (1006650015613).
5033250078035 is a wasteful number, since it uses less digits than its factorization.
5033250078035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1006650015612.
The product of its (nonzero) digits is 378000, while the sum is 41.
The spelling of 5033250078035 in words is "five trillion, thirty-three billion, two hundred fifty million, seventy-eight thousand, thirty-five".
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