Base | Representation |
---|---|
bin | 100100100111110101100… |
… | …1011110001001010011111 |
3 | 122211011221222121100010221 |
4 | 1021033223023301022133 |
5 | 1124431301210344320 |
6 | 14412142402542211 |
7 | 1026435110530051 |
oct | 111175313611237 |
9 | 18734858540127 |
10 | 5033352434335 |
11 | 16706a6259085 |
12 | 6935b7667967 |
13 | 2a6848b69b04 |
14 | 1358891398d1 |
15 | 8ade08093aa |
hex | 493eb2f129f |
5033352434335 has 16 divisors (see below), whose sum is σ = 6042673231776. Its totient is φ = 4024915406848.
The previous prime is 5033352434311. The next prime is 5033352434359. The reversal of 5033352434335 is 5334342533305.
It is an interprime number because it is at equal distance from previous prime (5033352434311) and next prime (5033352434359).
It is a cyclic number.
It is not a de Polignac number, because 5033352434335 - 217 = 5033352303263 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5033352434291 and 5033352434300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 191390907 + ... + 191417203.
It is an arithmetic number, because the mean of its divisors is an integer number (377667076986).
Almost surely, 25033352434335 is an apocalyptic number.
5033352434335 is a deficient number, since it is larger than the sum of its proper divisors (1009320797441).
5033352434335 is a wasteful number, since it uses less digits than its factorization.
5033352434335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41642.
The product of its (nonzero) digits is 2916000, while the sum is 43.
The spelling of 5033352434335 in words is "five trillion, thirty-three billion, three hundred fifty-two million, four hundred thirty-four thousand, three hundred thirty-five".
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